布尔谓词的惰性计算

/** 
来 自 
n o w    j a v a  . c o m
**/

public class Main {

  public static void main(String[] args) {

    double x = 3.14, y = 0.0;

    boolean test1, test2;


    test1 = (y != 0.0);

    test2 = (x / y > 2.0);


    System.out.println("Test1:" + test1 + " Test2:" + test2);

    System.out.println("We did not evaluate x/y that isequal to " + (x / y));


    if ((y == 0.0) || (x / y > 2.0)) { // Block

      System.out.println((x / y));

    }

  }

}