集册 Java实例教程 开发简洁的HTTP客户端

开发简洁的HTTP客户端

欢马劈雪     最近更新时间:2020-01-02 10:19:05

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开发简洁的HTTP客户端

import java.io.IOException;/*时代Java 提供*/

import java.net.URI;

import java.net.URISyntaxException;

import java.net.http.HttpRequest;

import java.net.http.HttpResponse;

import static java.net.http.HttpResponse.asFile;

import static java.net.http.HttpResponse.asString;

import static java.net.http.HttpResponse.ignoreBody;

import java.nio.file.Path;

import java.nio.file.Paths;

import static java.util.UUID.fromString;

import java.util.logging.Level;

import java.util.logging.Logger;/*n o w  j a v a  . c o m 提 供*/


public class Main {


    public static void main(String[] args) {


        HttpResponse r1;

        try {

            r1 = HttpRequest.create(new URI("http://nowjava.com/"))

                    .GET()

                    .response();


            int responseCode = r1.statusCode();

            if(responseCode == 200){

                System.out.println(r1.body(asStri
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