提示:您可在线编辑运行本教程的实例 - 运行实例,去试试!
返回给定数组中元素的索引。
/******************************************************************************* * Copyright 2014 uniVocity Software Pty Ltd * * Licensed under the Apache License, Version 2.0 (the "License"); * you may not use this file except in compliance with the License. * You may obtain a copy of the License at * * http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. * See the License for the specific language governing permissions and * limitations under the License. ******************************************************************************/ /** from 时代Java - nowjava.com**/ //package com.nowjava; public class Main { public static void main(String[] argv) throws Exception { Object[] array = new String[] { "1", "abc", "level", null, "nowjava.com", "asdf 123" }; Object element = "nowjava.com"; System.out.println(indexOf(array, element)); } /** * Returns the index of an element in a given array. * @param array the element array * @param element the element to be looked for in the array. * * @return the index of the given element in the array, or -1 if the element could not be found. */ public static int indexOf(Object[] array, Object element) { if (array == null) { throw new NullPointerException("Null array"); } /** * nowjava 提 供 **/ if (element == null) { for (int i = 0; i < array.length; i++) { if (array[i] == null) { return i; } } } else { if (element instanceof String && array instanceof String[]) { for (int i = 0; i < array.length; i++) { String e = String.valueOf(array[i]);