检查数组是否包含项。

/* Copyright 2005-2006 Tim Fennell

 *

 * Licensed under the Apache License, Version 2.0 (the "License");

 * you may not use this file except in compliance with the License.

 * You may obtain a copy of the License at

 *

 *     http://www.apache.org/licenses/LICENSE-2.0

 *

 * Unless required by applicable law or agreed to in writing, software

 * distributed under the License is distributed on an "AS IS" BASIS,

 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.

 * See the License for the specific language governing permissions and

 * limitations under the License.

 */

//package com.nowjava;/*来 自 nowjava*/


public class Main {

    public static void main(String[] argv) {

        Object[] arr = new String[] { "1", "abc", "level", null,

                "nowjava.com", "asdf 123" };

        Object item = "nowjava.com";

        System.out.println(contains(arr, item));

    }


    /**

     * Checks to see if an array contains an item. Works on unsorted arrays. If the array is

     * null this method will always return false.  If the item is null, will return true if the

     * array contains a null entry, false otherwise.  In all other cases, item.equals() is used

     * to determine equality.

     *

     * @param arr the array to scan for the item.

     * @param item the item to be looked for

     * @return true if item is contained in the array, false otherwise

     */

    public static boolean contains(Object[] arr, Object item) {

        if (arr == null)

            return false;

            /** from 
            时 代 J a v a - nowjava.com**/

        for (