如果字符串以任何给定术语开头，则编译可以与字符串匹配的模式。

/**来 自 NowJava.com - 时代Java**/

/*

 * Static String formatting and query routines.

 * Copyright (C) 2001-2005 Stephen Ostermiller

 * http://ostermiller.org/contact.pl?regarding=Java+Utilities

 *

 * This program is free software; you can redistribute it and/or modify

 * it under the terms of the GNU General Public License as published by

 * the Free Software Foundation; either version 2 of the License, or

 * (at your option) any later version.

 *

 * This program is distributed in the hope that it will be useful,

 * but WITHOUT ANY WARRANTY; without even the implied warranty of

 * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the

 * GNU General Public License for more details.

 *

 * See COPYING.TXT for details.

 */

//package com.nowjava;


import java.util.regex.Pattern;


public class Main {

    public static void main(String[] argv) {

        String[] terms = new String[] { "1", "abc", "level", null,

                "nowjava.com", "asdf 123" };

        System.out.println(getStartsWithAnyPattern(terms));

    }


    /**

     * Compile a pattern that can will match a string if the string

     * starts with any of the given terms.

     * <p>

     * Usage:<br>

     * <code>boolean b = getStartsWithAnyPattern(terms).matcher(s).matches();</code>

     * <p>

     * If multiple strings are matched against the same set of terms,

     * it is more efficient to reuse the pattern returned by this function.

     *

     * @param terms Array of search strings.

     * @return Compiled pattern that can be used to match a string to see if it starts with any of the terms.

     *

     * @since ostermillerutils 1.02.25

     */

    public static Pattern getStartsWithAnyPattern(String[] terms) {

        StringBuffer sb = new StringBuffer();

        sb.append("(?s)\\A");/*n o w j a v a . c o m - 时代Java 提供*/

        buildFindAnyPattern(terms, sb);

        sb.append(".*");

        return Pattern.compile(sb.toString());

    }


    /**

     * Build a regular expression that is each of the terms or'd together.

     *

     * @param terms a list of search terms.

     * @param sb place to build the regular expression.

     * @throws IllegalArgumentException if the length of terms is zero.

     *

     * @since ostermillerutils 1.02.25

     */

    private static void buildFindAnyPattern(String[] terms, StringBuffer sb) {

        if (terms.length == 0)

            throw new IllegalArgumentException(

                    "There must be at least one term to find.");

        sb.append("(?:");

        for (int i = 0; i < terms.length; i++) {

            if (i > 0)

                sb.append("|");

            sb.append("(?:");

            sb.append(escapeRegularExpressionLiteral(terms[i]));

            sb.append(")");

        }

        sb.append(")");

    }


    /**

     * Escapes characters that have special meaning to

     * regular expressions

     *

     * @param s String to be escaped

     * @return escaped String

     * @throws NullPointerException if s is null.

     *

     * @since ostermillerutils 1.02.25

     */

    public static String escapeRegularExpressionLiteral(String s) {

        // According to the documentation in the Pattern class:

        //

        // The backslash character ('\') serves to introduce escaped constructs,

        // as defined in the table above, as well as to quote characters that

        // otherwise would be interpreted as unescaped constructs. Thus the

        // expression \\ matches a single backslash and \{ matches a left brace.

        //

        // It is an error to use a backslash prior to any alphabetic character

        // that does not denote an escaped construct; these are reserved for future

        // extensions to the regular-expression language. A backslash may be used

        // prior to a non-alphabetic character regardless of whether that character

        // is part of an unescaped construct.

        //

        // As a result, escape everything except [0-9a-zA-Z]


        int length = s.length();

        int newLength = length;

        // first check for characters that might

        // be dangerous and calculate a length

        // of the string that has escapes.

        for (int i = 0; i < length; i++) {

            char c = s.charAt(i);

            if (!((c >= '0' && c <= '9') || (c >= 'A' && c <=