集册 Java实例教程 获取序列化的Lambda

获取序列化的Lambda

欢马劈雪     最近更新时间:2020-01-02 10:19:05

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获取序列化的Lambda
//时 代      J a v a   公   众 号 - nowjava.com 提 供

/*

 * Copyright 2015 Fizzed Inc.

 *

 * Licensed under the Apache License, Version 2.0 (the "License");

 * you may not use this file except in compliance with the License.

 * You may obtain a copy of the License at

 *

 *      http://www.apache.org/licenses/LICENSE-2.0

 *

 * Unless required by applicable law or agreed to in writing, software

 * distributed under the License is distributed on an "AS IS" BASIS,

 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.

 * See the License for the specific language governing permissions and

 * limitations under the License.

 */

//package com.nowjava;

import java.lang.invoke.SerializedLambda;

import java.lang.reflect.InvocationTargetException;

import java.lang.reflect.Method;


public class Main {

    static public SerializedLambda getSerializedLambda(Object function)

            throws Exception {

        if (function == null || !(function instanceof java.io.Serializable)) {

            throw new IllegalArgumentException();

        }


        for (Class<?> clazz = function.getClass(); clazz != null; clazz = clazz

                .getSuperclass()) {

            try {

                Method replaceMethod = clazz

                        .getDeclaredMethod("writeReplace");

                replaceMethod.setAccessible(true);
                /* 
                *来 自
                 nowjava
                */

                Object serializedForm = replaceMethod.invoke(function);


                if (serializedForm instanceof SerializedLambda) {

                    return (SerializedLambda) serializedForm;

                }

            } catch (NoSuchMethodError e) {

                // fall through the loop and try the next class

            } catch (NoSuchMethodException | SecurityException

                    | IllegalAccessException | 
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