集册 Java实例教程 从给定的合格参考值中提取名称。

从给定的合格参考值中提取名称。

欢马劈雪     最近更新时间:2020-01-02 10:19:05

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从给定的合格参考值中提取名称。

/*******************************************************************************

 * Copyright (c) 2004 Actuate Corporation.

 * All rights reserved. This program and the accompanying materials

 * are made available under the terms of the Eclipse Public License v1.0

 * which accompanies this distribution, and is available at

 * http://www.eclipse.org/legal/epl-v10.html

 *

 * Contributors:

 *  Actuate Corporation  - initial API and implementation

 *******************************************************************************///时   代    Java - nowjava.com



public class Main{

    public static void main(String[] argv){

        String qualifiedName = "nowjava.com";

        System.out.println(extractName(qualifiedName));

    }

    /**

     * Extracts the name from the given qualified reference value.

     * 

     * <p>

     * For example,

     * <ul>

     * <li>"style1" is extracted from "LibA.style1"

     * <li>"style1" is returned from "style1"

     * </ul>

     * 

     * @param qualifiedName

     *            the qualified reference value

     * @return the name

     */

    public static String extractName(String qualifiedName) {

        if (qualifiedName == null)

            return null;


        int pos = qualifiedName.indexOf('.');

        if (pos == -1)
        /*
         from nowjava.com - 时  代  Java 
        */

            return qualifiedName;


        return trimString(qualifiedName.substring(pos + 1));

    }

    /**

     * Trim a string. Removes leading and trailing blanks. If the resulting

     * string is empty, normalizes the string to an null string.

     * 

     * @param value

     *            the string to trim

     * @return the trimmed string, or null if the string is empty

     */


    
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