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对字符串内的字符进行排序
public class Anagram { /**来自 n o w j a v a . c o m**/ /** * Tests whether the passed-in strings are anagrams -- * containing the exact same number of each letter. * Punctuation, case, and order don't matter. * * @return true if the strings are anagrams; otherwise, false */ public static boolean areAnagrams(String string1, String string2) { String workingCopy1 = removeJunk(string1); String workingCopy2 = removeJunk(string2); workingCopy1 = workingCopy1.toLowerCase(); workingCopy2 = workingCopy2.toLowerCase(); workingCopy1 = sort(workingCopy1); workingCopy2 = sort(workingCopy2); return workingCopy1.equals(workingCopy2); }/*来自 时 代 Java - nowjava.com*/ /** * Removes punctuation & spaces -- everything except * letters from the passed-in string. * * @return a stripped copy of the passed-in string */ protected static String removeJunk(String string) { int i, len = string.length(); StringBuilder dest = new StringBuilder(len); char c; for (i = (len - 1); i >= 0; i--) { c = string.charAt(i); if (Character.isLetter(c)) { dest.append(c); } } return dest.toString(); } /** * Sorts the passed-in string. * * @return a sorted copy of the passed-in string */ protected static String sort(String string) { char[] charArray = string.toCharArray(); java.util.Arrays.sort(charArray); return new String(charArray); } public static void main(String[] args) { String string1 = "Cosmo and Laine:"; String string2 = "Maid, clean soon!"; System.out.println(); System.out.println("Testing whether the following " + "strings are anagrams:"); System.out.println(" String 1: " + string1); System.out.println(" String 2: " + string2); System.out.println(); if (areAnagrams(string1, string2)) { System.out.println("They ARE anagrams!"); } else { System.out.println("They are NOT anagrams!"); } System.out.println(); } }