Java 检查Ip掩码
检查Ip掩码
实例源码：
源代码：
执行
执行中...
x
1
2
3
//package com.nowjava;/**来 自 n o w j a v a . c o m**/4
5
6
public class Main {7
8
public static void main(String[] argv) throws Exception {9
10
String ip = "nowjava.com";11
12
System.out.println(checkIpMask(ip));13
14
}15
16
17
public static String checkIpMask(String ip) {18
19
String ipParts[] = ip.split("\\.");20
21
if (ipParts.length != 4)22
23
return "IP address must have 4 parts";24
25
String message = checkIpMaskPart(ipParts[0]);26
27
if (message != null)28
29
return message;30
31
message = checkIpMaskPart(ipParts[1]);32
33
if (message != null)34
35
return message;36
37
message = checkIpMaskPart(ipParts[2]);/*时 代 J a v a - nowjava.com 提 供*/38
39
if (message != null)40
41
return message;42
43
message = checkIpMaskPart(ipParts[3]);44
45
if (message != null)46
47
return message;48
49
else50
51
return null;52
53
}54
55
56
private static String checkIpMaskPart(String part) {57
58
int dash;59
60
if ("*".equals(part))61
62
return null;63
64
dash = part.indexOf('-');65
66
if (dash == -1) {67
68
int value = Integer.parseInt(part);69
70
if (value < 0 || value > 255)71
72
return (new StringBuilder())73
74
.append("Value out of range in '").append(part)75
76
.append("'").toString();77
78
//break MISSING_BLOCK_LABEL_219;79
80
}81
82
int from;83
84
from = Integer.parseInt(part.substring(0, dash));85
86
if (from < 0 || from > 255)87
88
return (new StringBuilder())89
90
.append("'From' value out of range in '").append(part)91
92
.append("'").toString();93
94
int to;95
96
try {97
98
to = Integer.parseInt(part.substring(dash + 1));99
100
if (to < 0 || to > 255)101
102
return (new StringBuilder())103
104
.append("'To' value out of range in '")105
106
.append(part).append("'").toString();107
108
} catch (NumberFormatException e) {109
/**代码未完, 请加载全部代码(NowJava.com).**/执行结果：
本文系作者在时代Java发表，未经许可，不得转载。如有侵权，请联系nowjava@qq.com删除。
编辑于
关注时代Java