时代Java，与您同行！关注微信公众号，关注前沿技术，微信搜索：nowjava或时代Java，也可点击这里扫码关注

时代Java

Java 如果给定的int数组具有相同的长度并以相同的顺序包含相同的值，则返回

欢马劈雪

工程师 (已认证)

原创分享签约作者

发表于实例源码

387

如果给定的int数组具有相同的长度并以相同的顺序包含相同的值，则返回

实例源码：

源代码：

执行

执行中...

/**来自 
 N o w  J a v a  .   c o m**/

You may freely copy, distribute, modify and use this class as long

as the original author attribution remains intact.  See message

below.

//package com.nowjava;

public class Main {

public static void main(String[] argv) throws Exception {

int[] first = new int[] { 34, 35, 36, 37, 37, 37, 67, 68, 69 };

int[] second = new int[] { 34, 35, 36, 37, 37, 37, 67, 68, 69 };

System.out.println(equals(first, second));

}

/**

* Returns if the given int arrays have the same length

* and contain the same values in the same order

* @param first  the first array to compare

* @param second the second array to compare

* @return true if the given int arrays have the same length

*         and contain the same values in the same order

public static boolean equals(int[] first, int[] second) {

if (first == second)
        /* from 
        时代Java公众号 - nowjava.com*/

return true;

if (first == null || second == null)

return false;

if (first.length != second.length)

return false;

for (int i = 0; i < second.length; i++) {

if (first[i] != second[i])

return false;

}

return true;

}

/**

* Returns if the given byte arrays have the same length

* and contain the same values in the same order

* @param first  the first array to compare

* @param second the second array to compare

* @return true if the given byte arrays have the same length

*         and contain the same values in the same order

public static boolean equals(byte[] first, byte[] second) {

if (first == second)
/**代码未完, 请加载全部代码(NowJava.com).**/

编辑/阅读全部代码

执行结果：

本文系作者在时代Java发表，未经许可，不得转载。如有侵权，请联系nowjava@qq.com删除。

编辑于 2020-03-26 09:23:272020-03-26 09:23:27

实例源码

实例源码订阅