工程师 (已认证)
原创分享签约作者
A single delimiter can * consists of more than one character: It will still be considered as single delimiter string, rather * than as bunch of potential delimiter characters - in contrast to tokenizeToStringArray. * * @param str * the input String * @param delimiter * the delimiter between elements (this is a single delimiter, rather than a bunch individual * delimiter characters) * @return an array of the tokens in the list * @see #tokenizeToStringArray */ public static String[] delimitedListToStringArray(final String str, final String delimiter) { return delimitedListToStringArray(str, delimiter, null); } /** * Take a String which is a delimited list and convert it to a String array.
tokenizeToStringArray
A single delimiter can * consists of more than one character: It will still be considered as single delimiter string, rather * than as bunch of potential delimiter characters - in contrast to tokenizeToStringArray. * * @param str * the input String * @param delimiter * the delimiter between elements (this is a single delimiter, rather than a bunch individual * delimiter characters) * @param charsToDelete * a set of characters to delete. Useful for deleting unwanted line breaks: e.g. "\r\n\f" will * delete all new lines and line feeds in a String. * @return an array of the tokens in the list * @see #tokenizeToStringArray */ public static String[] delimitedListToStringArray(final String str, final String delimiter, final String charsToDelete) { if (str == null) return new String[0]; if (delimiter == null) return new String[] { str }; final List result = new ArrayList(); if ("".equals(delimiter)) { for (int i = 0; i < str.length(); i++) { result.add(deleteAny(str.substring(i, i + 1), charsToDelete)); } } else { int pos = 0; int delPos; while ((delPos = str.indexOf(delimiter, pos)) != -1) { result.add(deleteAny(str.substring(pos, delPos), charsToDelete)); pos = delPos + delimiter.length(); } if ((str.length() > 0) && (pos <= str.length())) { // Add rest of String, but not in case of empty input. result.add(deleteAny(str.substring(pos), charsToDelete)); } } return toStringArray(result); } /** * Delete any character in a given String. * * @param inString * the original String * @param charsToDelete * a set of characters to delete. E.g. "az\n" will delete 'a's, 'z's and new lines. * @return the resulting String */ public static String deleteAny(final String inString, final String charsToDelete) { if (!hasLength(inString) || !hasLength(charsToDelete)) return inString; final StringBuilder sb = new StringBuilder(); for (int i = 0; i < inString.length(); i++) { final char c = inString.charAt(i); if (charsToDelete.indexOf(c) == -1) { sb.append(c); } } return sb.toString(); } /** * Copy the given Collection into a String array. The Collection must contain String elements only. * * @param collection * the Collection to copy * @return the String array (null if the passed-in Collection was null) */ public static String[] toStringArray(final Collection collection) { if (collection == null) return null; return collection.toArray(new String[collection.size()]); } /** * Copy the given Enumeration into a String array. The Enumeration must contain String elements only. * * @param enumeration * the Enumeration to copy * @return the String array (null if the passed-in Enumeration was null) */ public static String[] toStringArray( final Enumeration enumeration) { if (enumeration == null) return null; final List list = Collections.list(enumeration); return list.toArray(new String[list.size()]); } /** * Check that the given CharSequence is neither null nor of length 0. Note: Will return /**代码未完, 请加载全部代码(NowJava.com).**/
null
本文系作者在时代Java发表,未经许可,不得转载。如有侵权,请联系nowjava@qq.com删除。
分享文章到朋友圈
关注时代Java