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Java 获取名称减去完整文件名中的路径。
获取名称减去完整文件名的路径。
实例源码：
源代码：
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/**3
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* Licensed to Jasig under one or more contributor license5
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* agreements. See the NOTICE file distributed with this work7
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* for additional information regarding copyright ownership.9
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* Jasig licenses this file to you under the Apache License,11
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* Version 2.0 (the "License"); you may not use this file13
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* except in compliance with the License. You may obtain a15
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* copy of the License at:17
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*19
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* http://www.apache.org/licenses/LICENSE-2.021
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*23
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* Unless required by applicable law or agreed to in writing,25
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* software distributed under the License is distributed on27
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* an "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY29
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* KIND, either express or implied. See the License for the31
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* specific language governing permissions and limitations33
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* under the License.35
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*/37
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//package com.nowjava;//来 自 nowjava39
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public class Main {42
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public static void main(String[] argv) throws Exception {44
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String filename = "nowjava.com";46
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System.out.println(getName(filename));48
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}50
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/**53
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* The Unix separator character.55
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*/57
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private static final char UNIX_SEPARATOR = '/';59
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/**61
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* The Windows separator character.63
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*/65
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private static final char WINDOWS_SEPARATOR = '\\';67
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/**70
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* Gets the name minus the path from a full filename.72
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* <p>74
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* This method will handle a file in either Unix or Windows format.76
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* The text after the last forward or backslash is returned.78
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* <pre>80
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* a/b/c.txt --> c.txt82
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* a.txt --> a.txt84
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* a/b/c --> c86
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* a/b/c/ --> ""88
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* </pre>90
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* <p>92
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* The output will be the same irrespective of the machine that the code is running on.94
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*96
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* @param filename the filename to query, null returns null98
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* @return the name of the file without the path, or an empty string if none exists100
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*//*时 代 Java 公 众 号 - nowjava.com*/102
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static String getName(String filename) {104
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if (filename == null) {106
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return null;108
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}110
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int index = indexOfLastSeparator(filename);112
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return filename.substring(index + 1);114
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}116
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/**119
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* Returns the index of the last directory separator character.121
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* <p>123
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* This method will handle a file in either Unix or Windows format.125
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* The position of the last forward or backslash is returned.127
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* <p>129
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* The output will be the same irrespective of the machine that the code is running on.131
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* 133
/**代码未完, 请加载全部代码(NowJava.com).**/执行结果：
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