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Java 重新实现equals（）和hashCode（）方法的智能点类

欢马劈雪

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重新实现equals（）和hashCode（）方法的智能点类

实例源码：

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public class Main {/**来自 n o w j a v a . c o m**/

public static void main(String[] args) {

Point pt1 = new Point(10, 10);

Point pt2 = new Point(10, 10);

Point pt3 = new Point(12, 19);

Point pt4 = pt1;

System.out.println("pt1 == pt1: " + (pt1 == pt1));

System.out.println("pt1.equals(pt1): " + pt1.equals(pt1));

System.out.println("pt1 == pt2: " + (pt1 == pt2));

System.out.println("pt1.equals(pt2): " + pt1.equals(pt2));

System.out.println("pt1 == pt3: " + (pt1 == pt3));/** 时代Java - nowjava.com 提 供 **/

System.out.println("pt1.equals(pt3): " + pt1.equals(pt3));

System.out.println("pt1 == pt4: " + (pt1 == pt4));

System.out.println("pt1.equals(pt4): " + pt1.equals(pt4));

}

class Point {

private int x;

private int y;

public Point(int x, int y) {

this.x = x;

this.y = y;

}

/* Re-implement the equals() method */

public boolean equals(Object otherObject) {

// Are the same?

if (this == otherObject) {

return true;

}

// Is otherObject a null reference?

if (otherObject == null) {

return false;

}

// Do they belong to the same class?

if (this.getClass() != otherObject.getClass()) {

return false;

}

// Get the reference of otherObject in a SmartPoint variable

Point otherPoint = (Point) otherObject;

// Do they have the same x and y co-ordinates
/**代码未完, 请加载全部代码(NowJava.com).**/

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编辑于 2020-03-26 09:23:272020-03-26 09:23:27

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